Jar A contains only 50-cent coins and Jar B contains only 10-cent coins. There are 23 more coins in Jar B than in Jar A. The amount of money in Jar A is $1.70 more than the amount of money in Jar B. Find the total amount of money in both jars.
| |
Jar A |
Jar B |
| Number |
1 u |
1 u + 23 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 230 |
$1 = 100¢
$1.70 = 170¢
Total value of 50¢ coins in Jar A
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar B
= 10(1 u + 23)
= 10 u + 230
The amount of money in Jar A is $1.70 more than the amount of money in Jar B. If another 170¢ is added into Jar B, the total value of coins in Jar A and Jar B will be the same.
50 u = 10 u + 230 + 170
50 u - 10 u = 400
40 u = 400
1 u = 400 ÷ 40 = 10
Total amount in both jars
= 50 u + (10 u + 230)
= 60 u + 230
= (60 x 10) + 230
= 600 + 230
= 830¢
830¢ = $8.30
Answer(s): $8.30
