Coin Box Y contains only 50-cent coins and Coin Box Z contains only 5-cent coins. There are 19 more coins in Coin Box Z than in Coin Box Y. The amount of money in Coin Box Y is $2.65 more than the amount of money in Coin Box Z. Find the total amount of money in both coin boxes.
|
Coin Box Y |
Coin Box Z |
Number |
1 u |
1 u + 19 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 95 |
$1 = 100¢
$2.65 = 265¢
Total value of 50¢ coins in Coin Box Y
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box Z
= 5(1 u + 19)
= 5 u + 95
The amount of money in Coin Box Y is $2.65 more than the amount of money in Coin Box Z. If another 265¢ is added into Coin Box Z, the total value of coins in Coin Box Y and Coin Box Z will be the same.
50 u = 5 u + 95 + 265
50 u - 5 u = 360
45 u = 360
1 u = 360 ÷ 45 = 8
Total amount in both coin boxes
= 50 u + (5 u + 95)
= 55 u + 95
= (55 x 8) + 95
= 440 + 95
= 535¢
535¢ = $5.35
Answer(s): $5.35