Jar L contains only 50-cent coins and Jar M contains only 5-cent coins. There are 18 more coins in Jar M than in Jar L. The amount of money in Jar L is $3.60 more than the amount of money in Jar M. Find the total amount of money in both jars.
|
Jar L |
Jar M |
Number |
1 u |
1 u + 18 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 90 |
$1 = 100¢
$3.60 = 360¢
Total value of 50¢ coins in Jar L
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar M
= 5(1 u + 18)
= 5 u + 90
The amount of money in Jar L is $3.60 more than the amount of money in Jar M. If another 360¢ is added into Jar M, the total value of coins in Jar L and Jar M will be the same.
50 u = 5 u + 90 + 360
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both jars
= 50 u + (5 u + 90)
= 55 u + 90
= (55 x 10) + 90
= 550 + 90
= 640¢
640¢ = $6.40
Answer(s): $6.40