Tin Can E contains only 50-cent coins and Tin Can F contains only 10-cent coins. There are 15 more coins in Tin Can F than in Tin Can E. The amount of money in Tin Can E is $1.70 more than the amount of money in Tin Can F. Find the total amount of money in both tin cans.
| |
Tin Can E |
Tin Can F |
| Number |
1 u |
1 u + 15 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 150 |
$1 = 100¢
$1.70 = 170¢
Total value of 50¢ coins in Tin Can E
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can F
= 10(1 u + 15)
= 10 u + 150
The amount of money in Tin Can E is $1.70 more than the amount of money in Tin Can F. If another 170¢ is added into Tin Can F, the total value of coins in Tin Can E and Tin Can F will be the same.
50 u = 10 u + 150 + 170
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both tin cans
= 50 u + (10 u + 150)
= 60 u + 150
= (60 x 8) + 150
= 480 + 150
= 630¢
630¢ = $6.30
Answer(s): $6.30
