Tin Can K contains only 50-cent coins and Tin Can L contains only 5-cent coins. There are 12 more coins in Tin Can L than in Tin Can K. The amount of money in Tin Can K is $1.65 more than the amount of money in Tin Can L. Find the total amount of money in both tin cans.
| |
Tin Can K |
Tin Can L |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 60 |
$1 = 100¢
$1.65 = 165¢
Total value of 50¢ coins in Tin Can K
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can L
= 5(1 u + 12)
= 5 u + 60
The amount of money in Tin Can K is $1.65 more than the amount of money in Tin Can L. If another 165¢ is added into Tin Can L, the total value of coins in Tin Can K and Tin Can L will be the same.
50 u = 5 u + 60 + 165
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both tin cans
= 50 u + (5 u + 60)
= 55 u + 60
= (55 x 5) + 60
= 275 + 60
= 335¢
335¢ = $3.35
Answer(s): $3.35
