Jar L contains only 50-cent coins and Jar M contains only 5-cent coins. There are 17 more coins in Jar M than in Jar L. The amount of money in Jar L is $3.20 more than the amount of money in Jar M. Find the total amount of money in both jars.
|
Jar L |
Jar M |
Number |
1 u |
1 u + 17 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 85 |
$1 = 100¢
$3.20 = 320¢
Total value of 50¢ coins in Jar L
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar M
= 5(1 u + 17)
= 5 u + 85
The amount of money in Jar L is $3.20 more than the amount of money in Jar M. If another 320¢ is added into Jar M, the total value of coins in Jar L and Jar M will be the same.
50 u = 5 u + 85 + 320
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both jars
= 50 u + (5 u + 85)
= 55 u + 85
= (55 x 9) + 85
= 495 + 85
= 580¢
580¢ = $5.80
Answer(s): $5.80