Bottle C contains only 50-cent coins and Bottle D contains only 5-cent coins. There are 14 more coins in Bottle D than in Bottle C. The amount of money in Bottle C is $3.80 more than the amount of money in Bottle D. Find the total amount of money in both bottles.
| |
Bottle C |
Bottle D |
| Number |
1 u |
1 u + 14 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 70 |
$1 = 100¢
$3.80 = 380¢
Total value of 50¢ coins in Bottle C
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bottle D
= 5(1 u + 14)
= 5 u + 70
The amount of money in Bottle C is $3.80 more than the amount of money in Bottle D. If another 380¢ is added into Bottle D, the total value of coins in Bottle C and Bottle D will be the same.
50 u = 5 u + 70 + 380
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both bottles
= 50 u + (5 u + 70)
= 55 u + 70
= (55 x 10) + 70
= 550 + 70
= 620¢
620¢ = $6.20
Answer(s): $6.20
