Jar Z contains only 50-cent coins and Jar A contains only 5-cent coins. There are 10 more coins in Jar A than in Jar Z. The amount of money in Jar Z is $3.55 more than the amount of money in Jar A. Find the total amount of money in both jars.
| |
Jar Z |
Jar A |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 50 |
$1 = 100¢
$3.55 = 355¢
Total value of 50¢ coins in Jar Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar A
= 5(1 u + 10)
= 5 u + 50
The amount of money in Jar Z is $3.55 more than the amount of money in Jar A. If another 355¢ is added into Jar A, the total value of coins in Jar Z and Jar A will be the same.
50 u = 5 u + 50 + 355
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both jars
= 50 u + (5 u + 50)
= 55 u + 50
= (55 x 9) + 50
= 495 + 50
= 545¢
545¢ = $5.45
Answer(s): $5.45
