Coin Box X contains only 50-cent coins and Coin Box Y contains only 10-cent coins. There are 19 more coins in Coin Box Y than in Coin Box X. The amount of money in Coin Box X is $1.30 more than the amount of money in Coin Box Y. Find the total amount of money in both coin boxes.
|
Coin Box X |
Coin Box Y |
Number |
1 u |
1 u + 19 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 190 |
$1 = 100¢
$1.30 = 130¢
Total value of 50¢ coins in Coin Box X
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box Y
= 10(1 u + 19)
= 10 u + 190
The amount of money in Coin Box X is $1.30 more than the amount of money in Coin Box Y. If another 130¢ is added into Coin Box Y, the total value of coins in Coin Box X and Coin Box Y will be the same.
50 u = 10 u + 190 + 130
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both coin boxes
= 50 u + (10 u + 190)
= 60 u + 190
= (60 x 8) + 190
= 480 + 190
= 670¢
670¢ = $6.70
Answer(s): $6.70