Tin Can Q contains only 50-cent coins and Tin Can R contains only 5-cent coins. There are 16 more coins in Tin Can R than in Tin Can Q. The amount of money in Tin Can Q is $1.90 more than the amount of money in Tin Can R. Find the total amount of money in both tin cans.
| |
Tin Can Q |
Tin Can R |
| Number |
1 u |
1 u + 16 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 80 |
$1 = 100¢
$1.90 = 190¢
Total value of 50¢ coins in Tin Can Q
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can R
= 5(1 u + 16)
= 5 u + 80
The amount of money in Tin Can Q is $1.90 more than the amount of money in Tin Can R. If another 190¢ is added into Tin Can R, the total value of coins in Tin Can Q and Tin Can R will be the same.
50 u = 5 u + 80 + 190
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both tin cans
= 50 u + (5 u + 80)
= 55 u + 80
= (55 x 6) + 80
= 330 + 80
= 410¢
410¢ = $4.10
Answer(s): $4.10
