Bag G contains only 50-cent coins and Bag H contains only 5-cent coins. There are 21 more coins in Bag H than in Bag G. The amount of money in Bag G is $1.20 more than the amount of money in Bag H. Find the total amount of money in both bags.
| |
Bag G |
Bag H |
| Number |
1 u |
1 u + 21 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 105 |
$1 = 100¢
$1.20 = 120¢
Total value of 50¢ coins in Bag G
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag H
= 5(1 u + 21)
= 5 u + 105
The amount of money in Bag G is $1.20 more than the amount of money in Bag H. If another 120¢ is added into Bag H, the total value of coins in Bag G and Bag H will be the same.
50 u = 5 u + 105 + 120
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both bags
= 50 u + (5 u + 105)
= 55 u + 105
= (55 x 5) + 105
= 275 + 105
= 380¢
380¢ = $3.80
Answer(s): $3.80
