Jar D contains only 50-cent coins and Jar E contains only 5-cent coins. There are 17 more coins in Jar E than in Jar D. The amount of money in Jar D is $1.40 more than the amount of money in Jar E. Find the total amount of money in both jars.
| |
Jar D |
Jar E |
| Number |
1 u |
1 u + 17 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 85 |
$1 = 100¢
$1.40 = 140¢
Total value of 50¢ coins in Jar D
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar E
= 5(1 u + 17)
= 5 u + 85
The amount of money in Jar D is $1.40 more than the amount of money in Jar E. If another 140¢ is added into Jar E, the total value of coins in Jar D and Jar E will be the same.
50 u = 5 u + 85 + 140
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both jars
= 50 u + (5 u + 85)
= 55 u + 85
= (55 x 5) + 85
= 275 + 85
= 360¢
360¢ = $3.60
Answer(s): $3.60
