Jar J contains only 50-cent coins and Jar K contains only 5-cent coins. There are 20 more coins in Jar K than in Jar J. The amount of money in Jar J is $3.50 more than the amount of money in Jar K. Find the total amount of money in both jars.
|
Jar J |
Jar K |
Number |
1 u |
1 u + 20 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 100 |
$1 = 100¢
$3.50 = 350¢
Total value of 50¢ coins in Jar J
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar K
= 5(1 u + 20)
= 5 u + 100
The amount of money in Jar J is $3.50 more than the amount of money in Jar K. If another 350¢ is added into Jar K, the total value of coins in Jar J and Jar K will be the same.
50 u = 5 u + 100 + 350
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both jars
= 50 u + (5 u + 100)
= 55 u + 100
= (55 x 10) + 100
= 550 + 100
= 650¢
650¢ = $6.50
Answer(s): $6.50