Tin Can S contains only 50-cent coins and Tin Can T contains only 5-cent coins. There are 12 more coins in Tin Can T than in Tin Can S. The amount of money in Tin Can S is $1.20 more than the amount of money in Tin Can T. Find the total amount of money in both tin cans.
|
Tin Can S |
Tin Can T |
Number |
1 u |
1 u + 12 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 60 |
$1 = 100¢
$1.20 = 120¢
Total value of 50¢ coins in Tin Can S
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can T
= 5(1 u + 12)
= 5 u + 60
The amount of money in Tin Can S is $1.20 more than the amount of money in Tin Can T. If another 120¢ is added into Tin Can T, the total value of coins in Tin Can S and Tin Can T will be the same.
50 u = 5 u + 60 + 120
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both tin cans
= 50 u + (5 u + 60)
= 55 u + 60
= (55 x 4) + 60
= 220 + 60
= 280¢
280¢ = $2.80
Answer(s): $2.80