Jar C contains only 50-cent coins and Jar D contains only 5-cent coins. There are 19 more coins in Jar D than in Jar C. The amount of money in Jar C is $1.75 more than the amount of money in Jar D. Find the total amount of money in both jars.
| |
Jar C |
Jar D |
| Number |
1 u |
1 u + 19 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 95 |
$1 = 100¢
$1.75 = 175¢
Total value of 50¢ coins in Jar C
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar D
= 5(1 u + 19)
= 5 u + 95
The amount of money in Jar C is $1.75 more than the amount of money in Jar D. If another 175¢ is added into Jar D, the total value of coins in Jar C and Jar D will be the same.
50 u = 5 u + 95 + 175
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both jars
= 50 u + (5 u + 95)
= 55 u + 95
= (55 x 6) + 95
= 330 + 95
= 425¢
425¢ = $4.25
Answer(s): $4.25
