Bag S contains only 50-cent coins and Bag T contains only 10-cent coins. There are 13 more coins in Bag T than in Bag S. The amount of money in Bag S is $1.90 more than the amount of money in Bag T. Find the total amount of money in both bags.
| |
Bag S |
Bag T |
| Number |
1 u |
1 u + 13 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 130 |
$1 = 100¢
$1.90 = 190¢
Total value of 50¢ coins in Bag S
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag T
= 10(1 u + 13)
= 10 u + 130
The amount of money in Bag S is $1.90 more than the amount of money in Bag T. If another 190¢ is added into Bag T, the total value of coins in Bag S and Bag T will be the same.
50 u = 10 u + 130 + 190
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both bags
= 50 u + (10 u + 130)
= 60 u + 130
= (60 x 8) + 130
= 480 + 130
= 610¢
610¢ = $6.10
Answer(s): $6.10
