Bag R contains only 50-cent coins and Bag S contains only 5-cent coins. There are 13 more coins in Bag S than in Bag R. The amount of money in Bag R is $1.15 more than the amount of money in Bag S. Find the total amount of money in both bags.
|
Bag R |
Bag S |
Number |
1 u |
1 u + 13 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 65 |
$1 = 100¢
$1.15 = 115¢
Total value of 50¢ coins in Bag R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag S
= 5(1 u + 13)
= 5 u + 65
The amount of money in Bag R is $1.15 more than the amount of money in Bag S. If another 115¢ is added into Bag S, the total value of coins in Bag R and Bag S will be the same.
50 u = 5 u + 65 + 115
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both bags
= 50 u + (5 u + 65)
= 55 u + 65
= (55 x 4) + 65
= 220 + 65
= 285¢
285¢ = $2.85
Answer(s): $2.85