Coin Box M contains only 50-cent coins and Coin Box N contains only 5-cent coins. There are 10 more coins in Coin Box N than in Coin Box M. The amount of money in Coin Box M is $1.30 more than the amount of money in Coin Box N. Find the total amount of money in both coin boxes.
| |
Coin Box M |
Coin Box N |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 50 |
$1 = 100¢
$1.30 = 130¢
Total value of 50¢ coins in Coin Box M
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box N
= 5(1 u + 10)
= 5 u + 50
The amount of money in Coin Box M is $1.30 more than the amount of money in Coin Box N. If another 130¢ is added into Coin Box N, the total value of coins in Coin Box M and Coin Box N will be the same.
50 u = 5 u + 50 + 130
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both coin boxes
= 50 u + (5 u + 50)
= 55 u + 50
= (55 x 4) + 50
= 220 + 50
= 270¢
270¢ = $2.70
Answer(s): $2.70
