Jar R contains only 50-cent coins and Jar S contains only 5-cent coins. There are 24 more coins in Jar S than in Jar R. The amount of money in Jar R is $1.95 more than the amount of money in Jar S. Find the total amount of money in both jars.
|
Jar R |
Jar S |
Number |
1 u |
1 u + 24 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 120 |
$1 = 100¢
$1.95 = 195¢
Total value of 50¢ coins in Jar R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar S
= 5(1 u + 24)
= 5 u + 120
The amount of money in Jar R is $1.95 more than the amount of money in Jar S. If another 195¢ is added into Jar S, the total value of coins in Jar R and Jar S will be the same.
50 u = 5 u + 120 + 195
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both jars
= 50 u + (5 u + 120)
= 55 u + 120
= (55 x 7) + 120
= 385 + 120
= 505¢
505¢ = $5.05
Answer(s): $5.05