Tin Can N contains only 50-cent coins and Tin Can P contains only 5-cent coins. There are 22 more coins in Tin Can P than in Tin Can N. The amount of money in Tin Can N is $3.40 more than the amount of money in Tin Can P. Find the total amount of money in both tin cans.
| |
Tin Can N |
Tin Can P |
| Number |
1 u |
1 u + 22 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 110 |
$1 = 100¢
$3.40 = 340¢
Total value of 50¢ coins in Tin Can N
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can P
= 5(1 u + 22)
= 5 u + 110
The amount of money in Tin Can N is $3.40 more than the amount of money in Tin Can P. If another 340¢ is added into Tin Can P, the total value of coins in Tin Can N and Tin Can P will be the same.
50 u = 5 u + 110 + 340
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both tin cans
= 50 u + (5 u + 110)
= 55 u + 110
= (55 x 10) + 110
= 550 + 110
= 660¢
660¢ = $6.60
Answer(s): $6.60
