Bottle S contains only 50-cent coins and Bottle T contains only 10-cent coins. There are 22 more coins in Bottle T than in Bottle S. The amount of money in Bottle S is $1.80 more than the amount of money in Bottle T. Find the total amount of money in both bottles.
|
Bottle S |
Bottle T |
Number |
1 u |
1 u + 22 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 220 |
$1 = 100¢
$1.80 = 180¢
Total value of 50¢ coins in Bottle S
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle T
= 10(1 u + 22)
= 10 u + 220
The amount of money in Bottle S is $1.80 more than the amount of money in Bottle T. If another 180¢ is added into Bottle T, the total value of coins in Bottle S and Bottle T will be the same.
50 u = 10 u + 220 + 180
50 u - 10 u = 400
40 u = 400
1 u = 400 ÷ 40 = 10
Total amount in both bottles
= 50 u + (10 u + 220)
= 60 u + 220
= (60 x 10) + 220
= 600 + 220
= 820¢
820¢ = $8.20
Answer(s): $8.20