Bottle E contains only 50-cent coins and Bottle F contains only 10-cent coins. There are 21 more coins in Bottle F than in Bottle E. The amount of money in Bottle E is $1.10 more than the amount of money in Bottle F. Find the total amount of money in both bottles.
|
Bottle E |
Bottle F |
Number |
1 u |
1 u + 21 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 210 |
$1 = 100¢
$1.10 = 110¢
Total value of 50¢ coins in Bottle E
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle F
= 10(1 u + 21)
= 10 u + 210
The amount of money in Bottle E is $1.10 more than the amount of money in Bottle F. If another 110¢ is added into Bottle F, the total value of coins in Bottle E and Bottle F will be the same.
50 u = 10 u + 210 + 110
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both bottles
= 50 u + (10 u + 210)
= 60 u + 210
= (60 x 8) + 210
= 480 + 210
= 690¢
690¢ = $6.90
Answer(s): $6.90