Tin Can M contains only 50-cent coins and Tin Can N contains only 10-cent coins. There are 18 more coins in Tin Can N than in Tin Can M. The amount of money in Tin Can M is $1.80 more than the amount of money in Tin Can N. Find the total amount of money in both tin cans.
| |
Tin Can M |
Tin Can N |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 180 |
$1 = 100¢
$1.80 = 180¢
Total value of 50¢ coins in Tin Can M
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can N
= 10(1 u + 18)
= 10 u + 180
The amount of money in Tin Can M is $1.80 more than the amount of money in Tin Can N. If another 180¢ is added into Tin Can N, the total value of coins in Tin Can M and Tin Can N will be the same.
50 u = 10 u + 180 + 180
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both tin cans
= 50 u + (10 u + 180)
= 60 u + 180
= (60 x 9) + 180
= 540 + 180
= 720¢
720¢ = $7.20
Answer(s): $7.20
