Tin Can R contains only 50-cent coins and Tin Can S contains only 5-cent coins. There are 11 more coins in Tin Can S than in Tin Can R. The amount of money in Tin Can R is $3.50 more than the amount of money in Tin Can S. Find the total amount of money in both tin cans.
|
Tin Can R |
Tin Can S |
Number |
1 u |
1 u + 11 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 55 |
$1 = 100¢
$3.50 = 350¢
Total value of 50¢ coins in Tin Can R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can S
= 5(1 u + 11)
= 5 u + 55
The amount of money in Tin Can R is $3.50 more than the amount of money in Tin Can S. If another 350¢ is added into Tin Can S, the total value of coins in Tin Can R and Tin Can S will be the same.
50 u = 5 u + 55 + 350
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both tin cans
= 50 u + (5 u + 55)
= 55 u + 55
= (55 x 9) + 55
= 495 + 55
= 550¢
550¢ = $5.50
Answer(s): $5.50