Bag A contains only 50-cent coins and Bag B contains only 5-cent coins. There are 17 more coins in Bag B than in Bag A. The amount of money in Bag A is $3.65 more than the amount of money in Bag B. Find the total amount of money in both bags.
| |
Bag A |
Bag B |
| Number |
1 u |
1 u + 17 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 85 |
$1 = 100¢
$3.65 = 365¢
Total value of 50¢ coins in Bag A
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag B
= 5(1 u + 17)
= 5 u + 85
The amount of money in Bag A is $3.65 more than the amount of money in Bag B. If another 365¢ is added into Bag B, the total value of coins in Bag A and Bag B will be the same.
50 u = 5 u + 85 + 365
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both bags
= 50 u + (5 u + 85)
= 55 u + 85
= (55 x 10) + 85
= 550 + 85
= 635¢
635¢ = $6.35
Answer(s): $6.35
