Jar T contains only 50-cent coins and Jar U contains only 5-cent coins. There are 20 more coins in Jar U than in Jar T. The amount of money in Jar T is $1.70 more than the amount of money in Jar U. Find the total amount of money in both jars.
| |
Jar T |
Jar U |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 100 |
$1 = 100¢
$1.70 = 170¢
Total value of 50¢ coins in Jar T
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar U
= 5(1 u + 20)
= 5 u + 100
The amount of money in Jar T is $1.70 more than the amount of money in Jar U. If another 170¢ is added into Jar U, the total value of coins in Jar T and Jar U will be the same.
50 u = 5 u + 100 + 170
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both jars
= 50 u + (5 u + 100)
= 55 u + 100
= (55 x 6) + 100
= 330 + 100
= 430¢
430¢ = $4.30
Answer(s): $4.30
