Coin Box X contains only 50-cent coins and Coin Box Y contains only 5-cent coins. There are 16 more coins in Coin Box Y than in Coin Box X. The amount of money in Coin Box X is $1.45 more than the amount of money in Coin Box Y. Find the total amount of money in both coin boxes.
|
Coin Box X |
Coin Box Y |
Number |
1 u |
1 u + 16 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 80 |
$1 = 100¢
$1.45 = 145¢
Total value of 50¢ coins in Coin Box X
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box Y
= 5(1 u + 16)
= 5 u + 80
The amount of money in Coin Box X is $1.45 more than the amount of money in Coin Box Y. If another 145¢ is added into Coin Box Y, the total value of coins in Coin Box X and Coin Box Y will be the same.
50 u = 5 u + 80 + 145
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both coin boxes
= 50 u + (5 u + 80)
= 55 u + 80
= (55 x 5) + 80
= 275 + 80
= 355¢
355¢ = $3.55
Answer(s): $3.55