Jar G contains only 50-cent coins and Jar H contains only 5-cent coins. There are 22 more coins in Jar H than in Jar G. The amount of money in Jar G is $2.50 more than the amount of money in Jar H. Find the total amount of money in both jars.
| |
Jar G |
Jar H |
| Number |
1 u |
1 u + 22 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 110 |
$1 = 100¢
$2.50 = 250¢
Total value of 50¢ coins in Jar G
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar H
= 5(1 u + 22)
= 5 u + 110
The amount of money in Jar G is $2.50 more than the amount of money in Jar H. If another 250¢ is added into Jar H, the total value of coins in Jar G and Jar H will be the same.
50 u = 5 u + 110 + 250
50 u - 5 u = 360
45 u = 360
1 u = 360 ÷ 45 = 8
Total amount in both jars
= 50 u + (5 u + 110)
= 55 u + 110
= (55 x 8) + 110
= 440 + 110
= 550¢
550¢ = $5.50
Answer(s): $5.50
