Jar X contains only 50-cent coins and Jar Y contains only 5-cent coins. There are 20 more coins in Jar Y than in Jar X. The amount of money in Jar X is $2.15 more than the amount of money in Jar Y. Find the total amount of money in both jars.
| |
Jar X |
Jar Y |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 100 |
$1 = 100¢
$2.15 = 215¢
Total value of 50¢ coins in Jar X
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar Y
= 5(1 u + 20)
= 5 u + 100
The amount of money in Jar X is $2.15 more than the amount of money in Jar Y. If another 215¢ is added into Jar Y, the total value of coins in Jar X and Jar Y will be the same.
50 u = 5 u + 100 + 215
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both jars
= 50 u + (5 u + 100)
= 55 u + 100
= (55 x 7) + 100
= 385 + 100
= 485¢
485¢ = $4.85
Answer(s): $4.85
