Tin Can C contains only 50-cent coins and Tin Can D contains only 5-cent coins. There are 15 more coins in Tin Can D than in Tin Can C. The amount of money in Tin Can C is $1.95 more than the amount of money in Tin Can D. Find the total amount of money in both tin cans.
| |
Tin Can C |
Tin Can D |
| Number |
1 u |
1 u + 15 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 75 |
$1 = 100¢
$1.95 = 195¢
Total value of 50¢ coins in Tin Can C
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can D
= 5(1 u + 15)
= 5 u + 75
The amount of money in Tin Can C is $1.95 more than the amount of money in Tin Can D. If another 195¢ is added into Tin Can D, the total value of coins in Tin Can C and Tin Can D will be the same.
50 u = 5 u + 75 + 195
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both tin cans
= 50 u + (5 u + 75)
= 55 u + 75
= (55 x 6) + 75
= 330 + 75
= 405¢
405¢ = $4.05
Answer(s): $4.05
