Pouch M contains only 50-cent coins and Pouch N contains only 5-cent coins. There are 25 more coins in Pouch N than in Pouch M. The amount of money in Pouch M is $2.35 more than the amount of money in Pouch N. Find the total amount of money in both pouches.
| |
Pouch M |
Pouch N |
| Number |
1 u |
1 u + 25 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 125 |
$1 = 100¢
$2.35 = 235¢
Total value of 50¢ coins in Pouch M
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Pouch N
= 5(1 u + 25)
= 5 u + 125
The amount of money in Pouch M is $2.35 more than the amount of money in Pouch N. If another 235¢ is added into Pouch N, the total value of coins in Pouch M and Pouch N will be the same.
50 u = 5 u + 125 + 235
50 u - 5 u = 360
45 u = 360
1 u = 360 ÷ 45 = 8
Total amount in both pouches
= 50 u + (5 u + 125)
= 55 u + 125
= (55 x 8) + 125
= 440 + 125
= 565¢
565¢ = $5.65
Answer(s): $5.65
