Tin Can W contains only 50-cent coins and Tin Can X contains only 10-cent coins. There are 10 more coins in Tin Can X than in Tin Can W. The amount of money in Tin Can W is $2.20 more than the amount of money in Tin Can X. Find the total amount of money in both tin cans.
| |
Tin Can W |
Tin Can X |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 100 |
$1 = 100¢
$2.20 = 220¢
Total value of 50¢ coins in Tin Can W
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can X
= 10(1 u + 10)
= 10 u + 100
The amount of money in Tin Can W is $2.20 more than the amount of money in Tin Can X. If another 220¢ is added into Tin Can X, the total value of coins in Tin Can W and Tin Can X will be the same.
50 u = 10 u + 100 + 220
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both tin cans
= 50 u + (10 u + 100)
= 60 u + 100
= (60 x 8) + 100
= 480 + 100
= 580¢
580¢ = $5.80
Answer(s): $5.80
