Jar N contains only 50-cent coins and Jar P contains only 10-cent coins. There are 17 more coins in Jar P than in Jar N. The amount of money in Jar N is $1.50 more than the amount of money in Jar P. Find the total amount of money in both jars.
|
Jar N |
Jar P |
Number |
1 u |
1 u + 17 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 170 |
$1 = 100¢
$1.50 = 150¢
Total value of 50¢ coins in Jar N
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar P
= 10(1 u + 17)
= 10 u + 170
The amount of money in Jar N is $1.50 more than the amount of money in Jar P. If another 150¢ is added into Jar P, the total value of coins in Jar N and Jar P will be the same.
50 u = 10 u + 170 + 150
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both jars
= 50 u + (10 u + 170)
= 60 u + 170
= (60 x 8) + 170
= 480 + 170
= 650¢
650¢ = $6.50
Answer(s): $6.50