Coin Box K contains only 50-cent coins and Coin Box L contains only 10-cent coins. There are 10 more coins in Coin Box L than in Coin Box K. The amount of money in Coin Box K is $1.40 more than the amount of money in Coin Box L. Find the total amount of money in both coin boxes.
| |
Coin Box K |
Coin Box L |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 100 |
$1 = 100¢
$1.40 = 140¢
Total value of 50¢ coins in Coin Box K
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box L
= 10(1 u + 10)
= 10 u + 100
The amount of money in Coin Box K is $1.40 more than the amount of money in Coin Box L. If another 140¢ is added into Coin Box L, the total value of coins in Coin Box K and Coin Box L will be the same.
50 u = 10 u + 100 + 140
50 u - 10 u = 240
40 u = 240
1 u = 240 ÷ 40 = 6
Total amount in both coin boxes
= 50 u + (10 u + 100)
= 60 u + 100
= (60 x 6) + 100
= 360 + 100
= 460¢
460¢ = $4.60
Answer(s): $4.60
