Coin Box A contains only 50-cent coins and Coin Box B contains only 5-cent coins. There are 20 more coins in Coin Box B than in Coin Box A. The amount of money in Coin Box A is $1.25 more than the amount of money in Coin Box B. Find the total amount of money in both coin boxes.
| |
Coin Box A |
Coin Box B |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 100 |
$1 = 100¢
$1.25 = 125¢
Total value of 50¢ coins in Coin Box A
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box B
= 5(1 u + 20)
= 5 u + 100
The amount of money in Coin Box A is $1.25 more than the amount of money in Coin Box B. If another 125¢ is added into Coin Box B, the total value of coins in Coin Box A and Coin Box B will be the same.
50 u = 5 u + 100 + 125
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both coin boxes
= 50 u + (5 u + 100)
= 55 u + 100
= (55 x 5) + 100
= 275 + 100
= 375¢
375¢ = $3.75
Answer(s): $3.75
