Bottle Z contains only 50-cent coins and Bottle A contains only 10-cent coins. There are 14 more coins in Bottle A than in Bottle Z. The amount of money in Bottle Z is $1.40 more than the amount of money in Bottle A. Find the total amount of money in both bottles.
|
Bottle Z |
Bottle A |
Number |
1 u |
1 u + 14 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 140 |
$1 = 100¢
$1.40 = 140¢
Total value of 50¢ coins in Bottle Z
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle A
= 10(1 u + 14)
= 10 u + 140
The amount of money in Bottle Z is $1.40 more than the amount of money in Bottle A. If another 140¢ is added into Bottle A, the total value of coins in Bottle Z and Bottle A will be the same.
50 u = 10 u + 140 + 140
50 u - 10 u = 280
40 u = 280
1 u = 280 ÷ 40 = 7
Total amount in both bottles
= 50 u + (10 u + 140)
= 60 u + 140
= (60 x 7) + 140
= 420 + 140
= 560¢
560¢ = $5.60
Answer(s): $5.60