Coin Box H contains only 50-cent coins and Coin Box J contains only 10-cent coins. There are 25 more coins in Coin Box J than in Coin Box H. The amount of money in Coin Box H is $1.10 more than the amount of money in Coin Box J. Find the total amount of money in both coin boxes.
| |
Coin Box H |
Coin Box J |
| Number |
1 u |
1 u + 25 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 250 |
$1 = 100¢
$1.10 = 110¢
Total value of 50¢ coins in Coin Box H
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box J
= 10(1 u + 25)
= 10 u + 250
The amount of money in Coin Box H is $1.10 more than the amount of money in Coin Box J. If another 110¢ is added into Coin Box J, the total value of coins in Coin Box H and Coin Box J will be the same.
50 u = 10 u + 250 + 110
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both coin boxes
= 50 u + (10 u + 250)
= 60 u + 250
= (60 x 9) + 250
= 540 + 250
= 790¢
790¢ = $7.90
Answer(s): $7.90
