Jar G contains only 50-cent coins and Jar H contains only 5-cent coins. There are 17 more coins in Jar H than in Jar G. The amount of money in Jar G is $2.30 more than the amount of money in Jar H. Find the total amount of money in both jars.
|
Jar G |
Jar H |
Number |
1 u |
1 u + 17 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 85 |
$1 = 100¢
$2.30 = 230¢
Total value of 50¢ coins in Jar G
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar H
= 5(1 u + 17)
= 5 u + 85
The amount of money in Jar G is $2.30 more than the amount of money in Jar H. If another 230¢ is added into Jar H, the total value of coins in Jar G and Jar H will be the same.
50 u = 5 u + 85 + 230
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both jars
= 50 u + (5 u + 85)
= 55 u + 85
= (55 x 7) + 85
= 385 + 85
= 470¢
470¢ = $4.70
Answer(s): $4.70