Coin Box Z contains only 50-cent coins and Coin Box A contains only 5-cent coins. There are 18 more coins in Coin Box A than in Coin Box Z. The amount of money in Coin Box Z is $3.15 more than the amount of money in Coin Box A. Find the total amount of money in both coin boxes.
| |
Coin Box Z |
Coin Box A |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 90 |
$1 = 100¢
$3.15 = 315¢
Total value of 50¢ coins in Coin Box Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box A
= 5(1 u + 18)
= 5 u + 90
The amount of money in Coin Box Z is $3.15 more than the amount of money in Coin Box A. If another 315¢ is added into Coin Box A, the total value of coins in Coin Box Z and Coin Box A will be the same.
50 u = 5 u + 90 + 315
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both coin boxes
= 50 u + (5 u + 90)
= 55 u + 90
= (55 x 9) + 90
= 495 + 90
= 585¢
585¢ = $5.85
Answer(s): $5.85
