Bottle X contains only 50-cent coins and Bottle Y contains only 10-cent coins. There are 17 more coins in Bottle Y than in Bottle X. The amount of money in Bottle X is $1.90 more than the amount of money in Bottle Y. Find the total amount of money in both bottles.
| |
Bottle X |
Bottle Y |
| Number |
1 u |
1 u + 17 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 170 |
$1 = 100¢
$1.90 = 190¢
Total value of 50¢ coins in Bottle X
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle Y
= 10(1 u + 17)
= 10 u + 170
The amount of money in Bottle X is $1.90 more than the amount of money in Bottle Y. If another 190¢ is added into Bottle Y, the total value of coins in Bottle X and Bottle Y will be the same.
50 u = 10 u + 170 + 190
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both bottles
= 50 u + (10 u + 170)
= 60 u + 170
= (60 x 9) + 170
= 540 + 170
= 710¢
710¢ = $7.10
Answer(s): $7.10
