Tin Can Z contains only 50-cent coins and Tin Can A contains only 10-cent coins. There are 13 more coins in Tin Can A than in Tin Can Z. The amount of money in Tin Can Z is $1.50 more than the amount of money in Tin Can A. Find the total amount of money in both tin cans.
|
Tin Can Z |
Tin Can A |
Number |
1 u |
1 u + 13 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 130 |
$1 = 100¢
$1.50 = 150¢
Total value of 50¢ coins in Tin Can Z
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can A
= 10(1 u + 13)
= 10 u + 130
The amount of money in Tin Can Z is $1.50 more than the amount of money in Tin Can A. If another 150¢ is added into Tin Can A, the total value of coins in Tin Can Z and Tin Can A will be the same.
50 u = 10 u + 130 + 150
50 u - 10 u = 280
40 u = 280
1 u = 280 ÷ 40 = 7
Total amount in both tin cans
= 50 u + (10 u + 130)
= 60 u + 130
= (60 x 7) + 130
= 420 + 130
= 550¢
550¢ = $5.50
Answer(s): $5.50