Jar H contains only 50-cent coins and Jar J contains only 5-cent coins. There are 23 more coins in Jar J than in Jar H. The amount of money in Jar H is $3.35 more than the amount of money in Jar J. Find the total amount of money in both jars.
| |
Jar H |
Jar J |
| Number |
1 u |
1 u + 23 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 115 |
$1 = 100¢
$3.35 = 335¢
Total value of 50¢ coins in Jar H
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar J
= 5(1 u + 23)
= 5 u + 115
The amount of money in Jar H is $3.35 more than the amount of money in Jar J. If another 335¢ is added into Jar J, the total value of coins in Jar H and Jar J will be the same.
50 u = 5 u + 115 + 335
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both jars
= 50 u + (5 u + 115)
= 55 u + 115
= (55 x 10) + 115
= 550 + 115
= 665¢
665¢ = $6.65
Answer(s): $6.65
