Tin Can B contains only 50-cent coins and Tin Can C contains only 10-cent coins. There are 12 more coins in Tin Can C than in Tin Can B. The amount of money in Tin Can B is $2.40 more than the amount of money in Tin Can C. Find the total amount of money in both tin cans.
| |
Tin Can B |
Tin Can C |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 120 |
$1 = 100¢
$2.40 = 240¢
Total value of 50¢ coins in Tin Can B
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can C
= 10(1 u + 12)
= 10 u + 120
The amount of money in Tin Can B is $2.40 more than the amount of money in Tin Can C. If another 240¢ is added into Tin Can C, the total value of coins in Tin Can B and Tin Can C will be the same.
50 u = 10 u + 120 + 240
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both tin cans
= 50 u + (10 u + 120)
= 60 u + 120
= (60 x 9) + 120
= 540 + 120
= 660¢
660¢ = $6.60
Answer(s): $6.60
