Tin Can Y contains only 50-cent coins and Tin Can Z contains only 5-cent coins. There are 12 more coins in Tin Can Z than in Tin Can Y. The amount of money in Tin Can Y is $3.90 more than the amount of money in Tin Can Z. Find the total amount of money in both tin cans.
| |
Tin Can Y |
Tin Can Z |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 60 |
$1 = 100¢
$3.90 = 390¢
Total value of 50¢ coins in Tin Can Y
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can Z
= 5(1 u + 12)
= 5 u + 60
The amount of money in Tin Can Y is $3.90 more than the amount of money in Tin Can Z. If another 390¢ is added into Tin Can Z, the total value of coins in Tin Can Y and Tin Can Z will be the same.
50 u = 5 u + 60 + 390
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both tin cans
= 50 u + (5 u + 60)
= 55 u + 60
= (55 x 10) + 60
= 550 + 60
= 610¢
610¢ = $6.10
Answer(s): $6.10
