Bag B contains only 50-cent coins and Bag C contains only 10-cent coins. There are 20 more coins in Bag C than in Bag B. The amount of money in Bag B is $1.60 more than the amount of money in Bag C. Find the total amount of money in both bags.
| |
Bag B |
Bag C |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 200 |
$1 = 100¢
$1.60 = 160¢
Total value of 50¢ coins in Bag B
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag C
= 10(1 u + 20)
= 10 u + 200
The amount of money in Bag B is $1.60 more than the amount of money in Bag C. If another 160¢ is added into Bag C, the total value of coins in Bag B and Bag C will be the same.
50 u = 10 u + 200 + 160
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both bags
= 50 u + (10 u + 200)
= 60 u + 200
= (60 x 9) + 200
= 540 + 200
= 740¢
740¢ = $7.40
Answer(s): $7.40
