Tin Can S contains only 50-cent coins and Tin Can T contains only 5-cent coins. There are 10 more coins in Tin Can T than in Tin Can S. The amount of money in Tin Can S is $2.65 more than the amount of money in Tin Can T. Find the total amount of money in both tin cans.
| |
Tin Can S |
Tin Can T |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 50 |
$1 = 100¢
$2.65 = 265¢
Total value of 50¢ coins in Tin Can S
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can T
= 5(1 u + 10)
= 5 u + 50
The amount of money in Tin Can S is $2.65 more than the amount of money in Tin Can T. If another 265¢ is added into Tin Can T, the total value of coins in Tin Can S and Tin Can T will be the same.
50 u = 5 u + 50 + 265
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both tin cans
= 50 u + (5 u + 50)
= 55 u + 50
= (55 x 7) + 50
= 385 + 50
= 435¢
435¢ = $4.35
Answer(s): $4.35
