Coin Box A contains only 50-cent coins and Coin Box B contains only 10-cent coins. There are 13 more coins in Coin Box B than in Coin Box A. The amount of money in Coin Box A is $2.30 more than the amount of money in Coin Box B. Find the total amount of money in both coin boxes.
| |
Coin Box A |
Coin Box B |
| Number |
1 u |
1 u + 13 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 130 |
$1 = 100¢
$2.30 = 230¢
Total value of 50¢ coins in Coin Box A
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box B
= 10(1 u + 13)
= 10 u + 130
The amount of money in Coin Box A is $2.30 more than the amount of money in Coin Box B. If another 230¢ is added into Coin Box B, the total value of coins in Coin Box A and Coin Box B will be the same.
50 u = 10 u + 130 + 230
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both coin boxes
= 50 u + (10 u + 130)
= 60 u + 130
= (60 x 9) + 130
= 540 + 130
= 670¢
670¢ = $6.70
Answer(s): $6.70
