Jar N contains only 50-cent coins and Jar P contains only 5-cent coins. There are 21 more coins in Jar P than in Jar N. The amount of money in Jar N is $1.65 more than the amount of money in Jar P. Find the total amount of money in both jars.
| |
Jar N |
Jar P |
| Number |
1 u |
1 u + 21 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 105 |
$1 = 100¢
$1.65 = 165¢
Total value of 50¢ coins in Jar N
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar P
= 5(1 u + 21)
= 5 u + 105
The amount of money in Jar N is $1.65 more than the amount of money in Jar P. If another 165¢ is added into Jar P, the total value of coins in Jar N and Jar P will be the same.
50 u = 5 u + 105 + 165
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both jars
= 50 u + (5 u + 105)
= 55 u + 105
= (55 x 6) + 105
= 330 + 105
= 435¢
435¢ = $4.35
Answer(s): $4.35
