Zane has 6 more 20-cent coins than 5-cent coins. After he used 12 of his 20-cent coins, the total value of 20-cent coins is $1.80 more than the total value of 5-cent coins. How many coins did he have at first?
|
20¢ |
5¢ |
Before |
1 u + 6 |
1 u |
Change |
- 12 |
|
After |
1 u - 6 |
1 u |
|
20¢ |
5¢ |
Number |
1 u - 6 |
1 u |
Value |
20 |
5 |
Total value |
20 u - 120 |
5 u |
$1 = 100¢
$1.80 = 180¢
Number of 20¢ coins in the end
= 1 u + 6 - 12
= 1 u - 6
Total value of 20¢ coins in the end
= 20 x (1 u - 6)
= 20 u - 120
Total value of 5¢ coins in the end
= 5 x 1 u
= 5 u
After using 12 20-cent coins, the value of 20-cent coins is 180¢ more than the value of 5-cent coins. If another 180¢ is added to the 5-cent coins, the total value of 20-cent coins and 5-cent coins will be the same.
20 u - 120 = 5 u + 180
20 u - 5 u = 180 + 120
15 u = 300
1 u = 300 ÷ 15 = 20
Number of coins that Zane had at first
= 1 u + 1 u + 6
= 2 u + 6
= (2 x 20) + 6
= 40 + 6
= 46
Answer(s): 46