Reggie has 6 more 50-cent coins than 10-cent coins. After he used 17 of his 50-cent coins, the total value of 50-cent coins is $4.90 more than the total value of 10-cent coins. How many coins did he have in the end?
|
50¢ |
10¢ |
Before |
1 u + 6 |
1 u |
Change |
- 17 |
|
After |
1 u - 11 |
1 u |
|
50¢ |
10¢ |
Number |
1 u - 11 |
1 u |
Value |
50 |
10 |
Total value |
50 u - 550 |
10 u |
$1 = 100¢
$4.90 = 490¢
Number of 50¢ coins in the end
= 1 u + 6 - 17
= 1 u - 11
Total value of 50¢ coins in the end
= 50 x (1 u - 11)
= 50 u - 550
Total value of 10¢ coins in the end
= 10 x 1 u
= 10 u
After using 17 50-cent coins, the value of 50-cent coins is 490¢ more than the value of 10-cent coins. If another 490¢ is added to the 10-cent coins, the total value of 50-cent coins and 10-cent coins will be the same.
50 u - 550 = 10 u + 490
50 u - 10 u = 490 + 550
40 u = 1040
1 u = 1040 ÷ 40 = 26
Number of coins that Reggie had in the end
= 1 u + 1 u - 11
= 2 u - 11
= (2 x 26) - 11
= 52 - 11
= 41
Answer(s): 41